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Speed, wavelength, and range — the acoustic ruler

Line up the four-piece set of speed of sound, frequency, wavelength, and round-trip time, and draw the first trade-off between range and resolution.

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The speed of sound is not constant

The speed of sound in seawater is not a fixed 1500 m/s. In practice it depends on temperature, salinity, and pressure (depth). Temperature dominates near the surface, while pressure becomes more important with increasing depth. In most of the open ocean, salinity tends to contribute less than temperature or pressure.

For an introduction, using a representative value near 1500 m/s is enough for the calculations. For precise ranging or when you need to account for refraction, however, you need a full sound-speed profile.

The Mackenzie sound-speed approximation

The simulator in this course and the minimum implementation in Chapter 7 both compute the speed of sound c from temperature, salinity, and depth using the Mackenzie (1981) 9-term approximation. The representative form of the equation is:

c [m/s] = 1448.96
        + 4.591 T − 5.304×10⁻² T²    + 2.374×10⁻⁴ T³   ← temperature terms
        + 1.340 (S − 35)                                ← salinity term
        + 1.630×10⁻² D + 1.675×10⁻⁷ D²                  ← depth terms
        − 1.025×10⁻² T (S − 35) − 7.139×10⁻¹³ T D³      ← interaction terms

Here T is temperature [°C], S is salinity [PSU], and D is depth [m]. The higher-order T terms capture the non-linear temperature dependence near the surface, and the D terms capture pressure dependence at depth. The salinity coefficient is just 1.34, which is small compared to the temperature coefficient 4.59 — the equation itself shows that salinity contributes relatively little. The Chapter 6 simulator uses this same equation to compute the speed of sound when you move the temperature, salinity, and depth sliders.

Speed c, frequency f, wavelength λ, and round-trip time t form the basic set Range is c×t/2; wavelength is c/f. Higher frequency means shorter wavelength. λ = c / f Outbound Return Transmit Receive Range = c × t / 2

Read wavelength as c / f

Wavelength is the length of one cycle: λ = c / f. The higher the frequency, the shorter the wavelength. Short wavelengths make it easier to resolve fine structure, but as we will see later, absorption also grows.

For example, with c = 1500 m/s and f = 30 kHz, the wavelength is 0.05 m — that is, 5 cm. Wavelength is also the yardstick for choosing array element spacing.

Convert round-trip time back to range

An active sonar measures the round-trip time from transmission to reception of the echo. One-way range is c × t / 2. What matters is keeping the units of the speed c and the time t consistent. Using m/s and s gives you meters directly.

The equation is simple, but it carries a lot of practical intuition. Double the range, and the time also doubles. Changing the frequency does not change the basic timing equation as long as c stays the same. Once those correspondences are internalized, the numbers in the simulator become much easier to read.

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Chapter 2 / Practice 1
Unanswered

Q6. The three dominant factors in the speed of sound

Choose the best combination of factors that primarily set the speed of sound in seawater.

Show hint
Near the surface think temperature; at depth think pressure.
Show reasoning
The speed of sound in seawater mainly depends on temperature, salinity, and pressure (depth).
Chapter 2 / Practice 2
Unanswered

Q7. Where salinity fits in

How should you rank the effect of salinity on the speed of sound, compared to temperature and pressure, in most open-ocean settings?

Show hint
DOSITS describes salinity as the smaller contributor in most locations.
Show reasoning
In most open-ocean environments, the effect of salinity is smaller than that of temperature or pressure. That said, in estuaries and coastal regions it is no longer negligible.
Chapter 2 / Practice 3
Unanswered

Q8. Compute the wavelength

Take c = 1500 m/s and f = 30 kHz. What is the wavelength λ = c / f in meters?

Show hint
30 kHz = 30000 Hz.
Show reasoning
1500 / 30000 = 0.05 m, so the wavelength is 5 cm.
Chapter 2 / Practice 4
Unanswered

Q9. Range from a 0.8-second round trip

Take the speed of sound as 1500 m/s. The echo returns 0.8 s later. What is the one-way range in meters?

Show hint
Half of the 0.8-s round trip corresponds to the distance traveled.
Show reasoning
1500 × 0.8 ÷ 2 = 600, so the one-way range is 600 m.
Chapter 2 / Practice 5
Unanswered

Q10. Double the frequency at the same speed of sound

If the speed of sound stays the same and the frequency doubles, what happens to the wavelength?

Show hint
λ = c / f.
Show reasoning
At constant speed of sound, doubling the frequency halves the wavelength.

Key takeaways from this chapter

  • The speed of sound depends on temperature, salinity, and pressure. In the open ocean, salinity contributes relatively little.
  • Wavelength is λ = c / f. Higher frequency means shorter wavelength.
  • The equation for range from round-trip time is distance = c × t / 2.